May 13, 2014 · 1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n. A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count how many 5 5 …

Aug 5, 2019 · 1000 1000 is the number of small cubes in the original cube. Each face of the original cube contains 10 × 10 = 100 10 × 10 = 100 small cubes, so the effect of removing the small cubes …

Oct 31, 2017 · It means "26 million thousands". Essentially just take all those values and multiply them by 1000 1000. So roughly $26 $ 26 billion in sales.

Aug 23, 2015 · here's what I've already come up with: Using Euler's conrgruence, one finds that 201720162015 ≡ 201720162015 mod ϕ(1000) mod 1000, 2017 2016 2015 ≡ 2017 2016 2015 mod ϕ …

I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses. Here are the seven solutions I've found (on the Internet)...

Jul 17, 2019 · I understand that changing the divisor multiplies the result by that, but why doesn't changing the numerator cancel that out? I found out somewhere else since posting, is there a way to …

A hypothetical example: You have a 1/1000 chance of being hit by a bus when crossing the street. However, if you perform the action of crossing the street 1000 times, then your chance of being ...

Feb 20, 2016 · 3 There are ⌊1000 17 ⌋ = 58 that are divisible by 17 You can compute the other two and subtract each from 1000, but you have subtracted the multiples of 17 ⋅ 19 (and the other two pairs) …

Jan 30, 2017 · For example, the sum of all numbers less than 1000 1000 is about 500, 000 500, 000. So, 168 1000 × 500, 000 168 1000 × 500, 000 or 84, 000 84, 000 should be in the right ballpark. …

Jun 27, 2018 · A big part of this problem is that the "1 in 1000" event can happen multiple times within our attempt. Compare this to if you have a special deck of playing cards with 1000 cards in it, exactly …